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8n^2-n-12=-8
We move all terms to the left:
8n^2-n-12-(-8)=0
We add all the numbers together, and all the variables
8n^2-1n-4=0
a = 8; b = -1; c = -4;
Δ = b2-4ac
Δ = -12-4·8·(-4)
Δ = 129
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$n_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$n_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$n_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-1)-\sqrt{129}}{2*8}=\frac{1-\sqrt{129}}{16} $$n_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-1)+\sqrt{129}}{2*8}=\frac{1+\sqrt{129}}{16} $
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